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authorThibaut Horel <thibaut.horel@gmail.com>2013-02-11 11:22:51 -0800
committerThibaut Horel <thibaut.horel@gmail.com>2013-02-11 11:23:29 -0800
commitda5d7f0d127f58b42c3dd4acdbd647a513e6b10d (patch)
treec46ca521546bf170a276d717d2a287db7f1e8f53
parente6861101d63540bace192193b45d4a1610188e36 (diff)
downloadrecommendation-da5d7f0d127f58b42c3dd4acdbd647a513e6b10d.tar.gz
Fix multiple labels error in proofs.tex
-rw-r--r--proofs.tex2
1 files changed, 1 insertions, 1 deletions
diff --git a/proofs.tex b/proofs.tex
index ee57762..ba22501 100644
--- a/proofs.tex
+++ b/proofs.tex
@@ -93,7 +93,7 @@ and \eqref{eq:bound2} respectively, we wish to chose for $C=C^*$ such that:
This equation has two solutions. Only one of those is such that $C(e-1) -6e
+2 \geq 0$. This solution is:
\begin{equation}\label{eq:constant}
- C^* = \frac{8e-1 + \sqrt{64e^2-24e + 9}}{2(e-1)} \label{eq:c}
+ C^* = \frac{8e-1 + \sqrt{64e^2-24e + 9}}{2(e-1)}
\end{equation}
For this solution, $\frac{2e\varepsilon}{C^*(e-1)- 6e + 2}\leq \varepsilon.$
Placing the expression of $C^*$ in \eqref{eq:bound1} and \eqref{eq:bound2}