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| author | Stratis Ioannidis <stratis@stratis-Latitude-E6320.(none)> | 2012-11-04 13:03:15 -0800 |
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| committer | Stratis Ioannidis <stratis@stratis-Latitude-E6320.(none)> | 2012-11-04 13:03:15 -0800 |
| commit | fe1eddfacaec77b0038abdb899d3f5a56352e8b4 (patch) | |
| tree | ef76a478b3e097f28cdb8c243fcaed02f2345832 | |
| parent | d0889b68f87578a9cbf5fd6112ef7a427b53b599 (diff) | |
| download | recommendation-fe1eddfacaec77b0038abdb899d3f5a56352e8b4.tar.gz | |
monotonicity
| -rw-r--r-- | main.tex | 26 |
1 files changed, 11 insertions, 15 deletions
@@ -15,7 +15,7 @@ This process terminates when no more items can be added to $S$ using \eqref{gree algorithm for \textsc{Knapsack}. However, in contrast to \textsc{Knapsack}, for general submodular functions, the marginal value of an element in \eqref{greedy} depends on the set to which it the element is added. -Unfortunately, even for the full information case, the greedy heuristic gives an +Unfortunately, even for the full information case, the greedy algorithm gives an unbounded approximation ratio. Let $i^* = \argmax_{i\in\mathcal{N}} V(i)$ be the element of maximum value (as a singleton set). It has been noted by Khuller \emph{et al.}~\cite{khuller} that for the maximum @@ -25,7 +25,7 @@ following result from Singer \cite{singer-influence} which follows from Chen \emph{et al.}~\cite{chen}: \stratis{Is it Singer or Chen? Also, we need to introduce $V(i)$ somewhere...} \begin{lemma}[Singer \cite{singer-influence}]\label{lemma:greedy-bound} -Let $S_G$ be the set computed by the greedy heuristic and define $i^*$: +Let $S_G$ be the set computed by the greedy algorithm and define $i^*$: \begin{displaymath} i^* = \argmax_{i\in\mathcal{N}} V(i) \end{displaymath} @@ -197,31 +197,27 @@ The mechanism is monotone. Consider an agent $i$ with cost $c_i$ that is selected by the mechanism, and suppose that she reports a cost $c_i'\leq c_i$, all the other costs staying the same. - - If $i\neq i^*$, since $s_i(c_i,c_{-i})=1$, - $L_\mathcal{N}(x^*) \geq C V(i^*)$ and $i\in S_G$. - By reporting a cost $c_i'\leq c_i$, $i$ may be selected at an earlier iteration of the greedy heuristic. + Suppose that when $i$ reports $c_i$, $L_{\mathcal{N}\setminus\{i^*\}}(x^*) \geq C V(i^*)$; as $s_i(c_i,c_{-i})$, $i\in S_G$. + By reporting a cost $c_i'\leq c_i$, $i$ may be selected at an earlier iteration of the greedy algorithm. %using the submodularity of $V$, we see that $i$ will satisfy the greedy %selection rule: %\begin{displaymath} % i = \argmax_{j\in\mathcal{N}\setminus S} \frac{V(S\cup\{j\}) % - V(S)}{c_j} %\end{displaymath} - %in an earlier iteration of the greedy heuristic. Let us denote by $S_i$ + %in an earlier iteration of the greedy heuristic. + Denote by $S_i$ (resp. $S_i'$) the set to which $i$ is added when reporting cost $c_i$ - (resp. $c_i'$). We have $S_i'\subseteq S_i$. Moreover: + (resp. $c_i'$). We have $S_i'\subseteq S_i$; in addition, $S_i'\subseteq S_G'$, the set selected greedily under $(c_i',c_{-i})$; if not, then greedy selection would terminate prior to selecting $i$ also when she reports $c_i$, a contradiction. Moreover, we have \begin{align*} c_i' & \leq c_i \leq \frac{B}{2}\frac{V(S_i\cup\{i\})-V(S_i)}{V(S_i\cup\{i\})}\\ & \leq \frac{B}{2}\frac{V(S_i'\cup\{i\})-V(S_i')}{V(S_i'\cup\{i\})} \end{align*} - Hence $i$ will still be included in the result set. - - If $i = i^*$, $i$ is included iff $L_\mathcal{N}(x^*) \leq C V(i^*)$. - Reporting $c_i'$ instead of $c_i$ does not change the value $V(i^*)$ nor - $L_\mathcal{N}(x^*)$ (which is computed over - $\mathcal{N}\setminus\{i^*\}$). Thus $i$ is still included by reporting - a different cost. + by the monotonicity and submodularity of $V$. Hence $i\in S_G'$. Moreover, as $L_{\mathcal{N}\setminus \{i^*\}}(x^*)$ is the optimal value of \eqref{relax} under relaxation $L_{\mathcal{N}}$, reducing the costs can only increase this value, so under $c'_i\leq c_i$ the greedy set is still allocated and $s_i(c_i',c_{-i}) =1$. + Suppose now that when $i$ reports $c_i$, $L_{\mathcal{N}\setminus \{i^*\}}(x^*) < C V(i^*)$. Then $s_i(c_i,c_{-1})=1$ iff $i = i^*$. + Reporting $c_{i^*}'\leq c_{i^*}$ does not change $V(i^*)$ nor + $L_{\mathcal{N}\setminus \{i^*\}}(x^*) \leq C V(i^*)$; thus $s_{i^*}(c_{i^*}',c_{-i^*})=1$. \end{proof} \begin{lemma}\label{lemma:budget-feasibility} |
