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Diffstat (limited to 'paper/sections/results.tex')
| -rw-r--r-- | paper/sections/results.tex | 2 |
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diff --git a/paper/sections/results.tex b/paper/sections/results.tex index 8a7b4f9..25f540a 100644 --- a/paper/sections/results.tex +++ b/paper/sections/results.tex @@ -203,7 +203,7 @@ with probability $1-\frac{1}{m}$. If $\theta_i = 0$ and $\hat \theta > \eta$, then $\|\hat \theta - \theta\|_2 \geq |\hat \theta_i-\theta_j| > \eta$, which is a contradiction. Therefore we get no false positives. If $\theta_i \leq \eta + \epsilon$, then $|\hat{\theta}_i- \theta_i| < \epsilon \implies \theta_j -> \eta$. Therefore, we get all strong parents. +> \eta$ and we get all strong parents. \end{proof} Assuming we know a lower bound $\alpha$ on $\Theta_{i,j}$, |