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authorThibaut Horel <thibaut.horel@gmail.com>2015-08-30 08:36:03 -0700
committerThibaut Horel <thibaut.horel@gmail.com>2015-08-30 08:36:03 -0700
commit7454e814592cefa0eeb37f6ecb33ea9bf77f4e09 (patch)
tree67985ab81e973bb3370108030d6761e22c487ff5 /final/main.tex
parent7eb00cfe5a7b7a37491a7a1d8f48b0bf642136b3 (diff)
downloadecon2099-7454e814592cefa0eeb37f6ecb33ea9bf77f4e09.tar.gz
Proof of the first conjecture
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@@ -523,10 +523,32 @@ extended, having made the appropriate changes, to the constrained case) as in th
Lemma~6 from \cite{babaioff} yields the following version of the core
decomposition lemma:
-\begin{conjecture}
+\begin{lemma}
$\Rev(\hat{x}, D)\leq \Val(D^C_\emptyset) + \sum_A p_A\Rev(\hat{x}_A,
D^T_A)$.
-\end{conjecture}
+\end{lemma}
+
+\begin{proof}
+ Similarly to the proof of Lemma 6 in \cite{babaioff}, we get:
+ \begin{displaymath}
+ \Rev(\hat{x}, D) \leq \sum_A p_A \Rev(\hat{x}_A, D_A)
+ \end{displaymath}
+ Using Corollary~\ref{cor}, we get that $\Rev(\hat{x}_A, D_A)
+ \leq \Val(D_A^C) + \Rev(\hat{x}_A, D_A^T)$. Hence:
+ \begin{align*}
+ \Rev(\hat{x}, D) &\leq \sum_A p_A\big(\Val(D_A^C) + \Rev(\hat{x}_A,
+ D_A^T) \big)\\
+ &= \sum_A p_A\Val(D_A^C) + \sum_A p_A \Rev(\hat{x}_A,
+ D_A)\\
+ &\leq \sum_A p_A\Val(D_{\emptyset}^C) + \sum_A p_A \Rev(\hat{x}_A,
+ D_A)\\
+ &= \Val(D_{\emptyset}^C) + \sum_A p_A \Rev(\hat{x}_A,
+ D_A)
+ \end{align*}
+ Where the second inequality used that $\Val(D_A^C)\leq
+ \Val(D_{\emptyset}^C)$ and where the last equality used $\sum_A p_A = 1$.
+\end{proof}
+
However, if we keep pushing in this direction, it seems that the approach fails
when trying to obtain the following: