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| author | Thibaut Horel <thibaut.horel@gmail.com> | 2015-03-05 12:51:43 -0500 |
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| committer | Thibaut Horel <thibaut.horel@gmail.com> | 2015-03-05 12:51:43 -0500 |
| commit | 96f5a11aec4e9a6c94eedc3167ac42b4f62c6f93 (patch) | |
| tree | 07c7d92b1cfdd8e54057cc6dda419bce357e8c25 /paper/sections/adaptivity.tex | |
| parent | 26e0b3c4128c6d8c215ee894b1f447f1984d55f0 (diff) | |
| download | fast-seeding-96f5a11aec4e9a6c94eedc3167ac42b4f62c6f93.tar.gz | |
Revert "ArXiv version"
This reverts commit 26e0b3c4128c6d8c215ee894b1f447f1984d55f0.
Diffstat (limited to 'paper/sections/adaptivity.tex')
| -rw-r--r-- | paper/sections/adaptivity.tex | 10 |
1 files changed, 5 insertions, 5 deletions
diff --git a/paper/sections/adaptivity.tex b/paper/sections/adaptivity.tex index 8e2e52f..d590408 100644 --- a/paper/sections/adaptivity.tex +++ b/paper/sections/adaptivity.tex @@ -149,10 +149,10 @@ adaptive policy is upper bounded by the optimal non-adaptive policy: % \end{displaymath} %\end{proposition} -The proof of this proposition can be found in Appendix~\ref{sec:ad-proofs} and -relies on the following fact: the optimal adaptive policy can be written as -a feasible non-adaptive policy, hence it provides a lower bound on the value of -the optimal non-adaptive policy. +The proof of this proposition can be found in the full version of the +paper~\cite{full} and relies on the following fact: the optimal adaptive policy +can be written as a feasible non-adaptive policy, hence it provides a lower +bound on the value of the optimal non-adaptive policy. \subsection{From Non-Adaptive to Adaptive Solutions}\label{sec:round} @@ -212,7 +212,7 @@ $S$ that we denote by $A(S)$. More precisely, denoting by $\text{OPT}_A$ the optimal value of the adaptive problem~\eqref{eq:problem}, we have the following proposition whose proof can -be found in Appendix~\ref{sec:ad-proofs}. +be found in the full version of this paper~\cite{full}. \begin{proposition}\label{prop:cr} Let $(S,\textbf{q})$ be an $\alpha$-approximate solution to the non-adaptive problem \eqref{eq:relaxed}, then $\mathrm{A}(S) \geq \alpha |
