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-\documentclass[10pt]{article}
-\usepackage{fullpage, amsmath, amssymb, amsthm, bbm}
-\usepackage[utf8x]{inputenc}
-
-\DeclareMathOperator{\E}{\mathbb{E}}
-\let\P\relax
-\DeclareMathOperator{\P}{\mathbb{P}}
-\newcommand{\ex}[1]{\E\left[#1\right]}
-\newcommand{\prob}[1]{\P\left[#1\right]}
-\newcommand{\reals}{\mathbb{R}}
-\newcommand{\ints}{\mathbb{N}}
-\renewcommand{\O}{\mathcal{O}}
-
-
-\newtheorem{proposition}{Proposition}
-\newtheorem{corollary}{Corollary}
-\newtheorem{problem}{Problem}
-\newtheorem{theorem}{Theorem}
-\newtheorem{claim}{Claim}
-\newtheorem{remark}{Remark}
-
-\title{Learn and/or Optimize}
-\author{}
-\date{}
-
-\begin{document}
-\maketitle
-
-\section{Preliminary Results}
-\label{sec:matrix_theory}
-
-\subsection{Generic Random Matrix Theory}
-We cite the following result from~\cite{vershynin2010introduction} (Remark 5.40):
-
-\begin{proposition}\label{prop:non_isotropic_isometry}
-Assume that $A$ is an $N \times n$ matrix whose rows $A_i$ are independent
-sub-gaussian random vectors in $\mathbb{R}^n$ with second moment matrix
-$\Sigma$. Then for every $t \geq 0$, the following inequality holds with
-probability at least: $1- 2 \exp(-ct^2)$: \begin{equation} \|\frac{1}{N} A^T A
-- \Sigma \| \leq \max(\delta, \delta^2) \ \text{where}\ \delta =
-C\sqrt{\frac{n}{N}} + \frac{t}{\sqrt{N}} \end{equation} where $C$, $c$ depend
-only on the subgaussian norm of the rows $K \equiv \max_i \| A_i\|_{\psi_2}$.
-\end{proposition}
-
-The following result is a simple corollary of
-Proposition~\ref{prop:non_isotropic_isometry}:
-
-\begin{corollary}\label{cor:number_of_rows_needed} Let $n \in \mathbb{N}$ and
- $k \in ]0,n[$. Assume that $A$ is an $N \times n$ matrix whose rows $A_i$ are
- independent Bernoulli variable vectors in $\mathbb{R}^n$ such that
- $\mathbb{P}(A_{i,j} = 1) = \frac{k}{n} = 1 - \mathbb{P}(A_{i,j} = 0)$ and let
- $\sigma \equiv \frac{k}{n}(1- \frac{k}{n}) \neq 0$, then if $N > {(C+1)}^2
- n/\sigma^2$, the matrix A has full row rank with probability at least $1 -
- e^{-cn}$, where $C, c$ are constant depending only on the subgaussian norm
- of the rows $K \equiv \sup_{p \geq 1}
- {\frac{1}{\sqrt{p}}(\mathbb{E}|A_1|^p)}^\frac{1}{p} = k$\footnote{Is this true?
- And how do the constants behave?} \end{corollary}
-
-\begin{proof} It is easy to compare the kernels of $A$ and $A^TA$ and notice
- that $rank(A) = rank(A^T A)$. Since $A^TA$ is an $n \times n$ matrix, it
- follows that if $A^TA$ is invertible, then $A$ has full row rank. In other
- words, if $A$ has smallest singular value $\sigma_{\min}(A) > 0$, then $A$
- has full row rank. Consider Prop.~\ref{prop:non_isotropic_isometry} with $t
- \equiv \sqrt{n}$ and with $N > {(C+1)}^{2} n$, then with probability $1 -
- 2\exp(-cn)$: \begin{equation} \|\frac{1}{N} A^T A - \sigma I \| \leq
- (C+1)\sqrt{\frac{n}{N}} \end{equation}
-
-It follows that for any vector $x \in \mathbb{R}^n$, $|\frac{1}{N}\|A x\|^2_2
--\sigma | \leq (C+1)\sqrt{\frac{n}{N}} \implies \|A x\|^2_2 \geq N\left(\sigma
-- (C+1)\sqrt{\frac{n}{N}}\right)$. If $N > {(C+1)}^2n/\sigma^2$, then
-$\sigma_{\min}(A) > 0$ with probability at least $1 - e^{-cn}$ \end{proof}
-
-\subsection{More Direct Approach}
-
-Here we work on $\mathbb{F}_2$. An $n\times n$ binary matrix can be seen as
-a matrix over $\mathbb{F}_2$. Let us assume that each row of $A$ is chosen
-uniformly at random among all binary rows of length $n$. A standard counting
-arguments shows that the number of non-singular matrices over $\mathbb{F}_2$
-is:
-\begin{displaymath}
- N_n = (2^n-1)(2^n - 2)\dots (2^n- 2^{n-1})
- = (2^n)^n\prod_{i=1}^n\left(1-\frac{1}{2^i}\right)
-\end{displaymath}
-
-Hence the probability that our random matrix $A$ is invertible is:
-\begin{displaymath}
- P_n = \prod_{i=1}^n\left(1-\frac{1}{2^i}\right)
-\end{displaymath}
-It is easy to see that $P_n$ is a decreasing sequence. Its limit is
-$\phi(\frac{1}{2})$ where $\phi$ is the Euler function. We have
-$\phi(\frac{1}{2})\approx
-0.289$ and $P_n$ converges
-exponentially fast to this constant (one way to see this is to use the
-Pentagonal number theorem).
-
-Hence, if we observe $\ell\cdot n$ uniformly random binary rows, the
-probability that they will have full column rank is at least:
-\begin{displaymath}
- P_{\ell\cdot n}\geq 1 - \left(1-\phi\left(\frac{1}{2}\right)\right)^{\ell}
-\end{displaymath}
-
-Note that this is the probability of having full column rank over
-$\mathbb{F}_2$. A standard linear algebra argument shows that this implies full
-column rank over $\mathbb{R}$.
-
-\paragraph{TODO:} Study the case where we only observe sets of size exactly
-$k$, or at most $k$. This amounts to replacing $2^n$ in the computation above
-by:
-\begin{displaymath}
-{n\choose k}\quad\text{or}\quad\sum_{j=0}^k{n\choose j}
-\end{displaymath}
-
-Thinking about it, why do we assume that the sample sets are of size exactly
-$k$. I think it would make more sense from the learning perspective to consider
-uniformly random sets. In this case, the above approach allows us to conclude
-directly.
-
-More generally, I think the “right” way to think about this is to look at $A$
-as the adjacency matrix of a random $k$-regular graph. There are tons of
-results about the probability of the adjacency matrix to be non singular.
-
-\section{Examples}
-
-\subsection{Generic Functions}
-
-\paragraph{TODO:} Add citations!
-
-These are generic examples and serve as building blocks for the applications
-below:
-\begin{itemize}
- \item $f(S) = g\left(\sum_{i\in S} w_i\right)$ for a concave
- $g:\reals\to\reals$ and weights $(w_i)_{i\in N}\in \reals_+^{|N|}$. Note
- that $f$ is monotone iff $g$ is monotone. In this case, $g$ does not
- matter for the purpose of optimization: the sets are in the same order
- with or without $g$, the only things which matter are the weights which
- serve as natural parameters for this class of functions. This class of
- functions contains:
- \begin{itemize}
- \item additive functions (when $g$ is the identity function).
- \item $f(S) = |S\cap X|$ for some set $X\subseteq N$. This is the
- case where the weights are $0/1$ and $g$ is the identity
- function.
- \item symmetric submodular functions: when the weights are all one.
- \item budget-additive functions, when $g:x\mapsto \min(B, x)$ for
- some $B$.
- \end{itemize}
- \item $f(S) = \max_{i\in S} w_i$ for weights $(w_i)_{i\in N}\in
- \reals_+^{|N|}$. This class of functions is also naturally parametrized
- by the weights.
- \item (weighted) matroid rank functions. Given a matroid $M$ over a ground
- set $N$, we define its rank function to be:
- \begin{displaymath}
- \forall S\subseteq N,\;
- r(S) = \max_{\substack{I\subseteq S\\I\in M}} |I|
- \end{displaymath}
- more generally, given a weight function $w:N\to\reals_+$, we define the
- weighted matroid rank function:
- \begin{displaymath}
- \forall S\subseteq N,\;
- r(S) = \max_{\substack{I\subseteq S\\I\in M}} \sum_{i\in I} w_i
- \end{displaymath}
-\end{itemize}
-
-\paragraph{Remark} The function $f(S)= \max_{i\in S}w_i$ is a weighted matroid
-rank function for the $1$-uniform matroid (the matroid where the independent
-sets are the sets of size at most one).
-
-\subsection{Applications}
-
-\begin{itemize}
- \item \emph{Coverage functions:} they can be written as a positive linear
- combination of matroid rank functions:
- \begin{displaymath}
- f(S) = \sum_{u\in\mathcal{U}} w_u c_u(S)
- \end{displaymath}
- where $c_u$ is the rank function of the matroid $M = \big\{ \emptyset,
- \{u\}\big\}$.
- \item \emph{Facility location:} (cite Bilmes) there is a universe
- $\mathcal{U}$ of locations and a proximity score $s_{i,j}$ for each
- pair of locations. We pick a subset of locations $S$ and each point in
- the universe is allocated to its closest location (the one with highest
- proximity):
- \begin{displaymath}
- f(S) = \sum_{u\in\mathcal{U}} \max_{v\in S} s_{u,v}
- \end{displaymath}
- This can be seen as a sum of weighted matroid rank functions: one for
- each location in the universe associated with a $1$-uniform matroid
- (other applications: job scheduling).
-
- \item \emph{Image segmentation:} (cite Jegelka) can be (in some cases)
- written as a graph cut function. For image segmentation the goal is to
- minimize the cut.
- \begin{displaymath}
- f(S) = \sum_{e\in E} w_e c_e(S)
- \end{displaymath}
- where $c_e(S)$ is one iff $e\in E(S,\bar{S})$. \textbf{TODO:} I think
- this can be written as a matroid rank function.
- \item \emph{Learning} (cite Krause) there is
- a hypothesis $A$ (a random variable) which is “refined” when more
- observations are made. Imagine that there is a finite set $X_1,\dots,
- X_n$ of possible observations (random variables). Then, assuming that
- the observations are independent conditioned on $A$, the information
- gain:
- \begin{displaymath}
- f(S) = H(A) - H\big(A\,|\,(X_i)_{i\in S}\big)
- \end{displaymath}
- is submodular. The $\log\det$ is the specific case of a linear
- hypothesis observed with additional independent Gaussian noise.
- \item \emph{Entropy:} Closely related to the previous one. If $(X_1,\dots,
- X_n)$ are random variables, then:
- $ f(S) = H(X_S) $ is submodular. In particular, if $(X_1,\dots,
- X_n)$ are jointly multivariate gaussian, then:
- \begin{displaymath}
- f(S) = c|S| + \frac{1}{2}\log\det X_SX_S^T
- \end{displaymath}
- for $c= 2\pi e...$ and we fall back to the usual $\log\det$ function.
- \item \emph{data subset selection/summarization:} in statistical machine
- translation, Bilmes used sum of concave over modular:
- \begin{displaymath}
- f(S) = \sum_{f} \lambda_f \phi\left(\sum_{e\in S}w_f(e)\right)
- \end{displaymath}
- where each $f$ represents a feature, $w_f(e)$ represents how much of
- $f$ element $e$ has, and $\phi$ captures decreasing marginal gain when
- we have a lot of a given feature.
- Facility location functions are also commonly used for subset selection.
- \item \emph{concave spectral functions} One would be tempted to say that
- any multivariate concave function of a modular function is submodular.
- This would be the natural generalization of concave over modular.
- However \textbf{this is not true in general}. However, a possible nice
- generalization is the following. Let $M$ be a symmetric $n\times
- n$ matrix, and $g$ is a ``matrix concave'' function. Then:
- \begin{displaymath}
- f(S) = \mathrm{Tr}\big(g(M_S)\big)
- \end{displaymath}
- is submodular. This contains the $\log\det$ (when $g$ is the matrix
- $\log$) but tons of other functions (like quantum entropy).
-\end{itemize}
-In summary, the two most general classes of submodular functions (which capture
-all the examples known to man) are: sums of matrix concave functions and sums
-of matroid rank functions. Sums of concave over modular are also nice if we
-want to start with a simpler example.
-
-\section{Passive Optimization}
-
-Let $\Omega$ be the universe of elements and $f$ a function defined on subsets
-of $\Omega$: $f : S \in 2^{[\Omega]} \mapsto f(S) \in \mathbb{R}$. Let $K$ be a
-collection of sets of $2^{[\Omega]}$, which we call \emph{constraints}. Let
-$S^*_K$ be any solution to $\max_{S \in K} f(S)$, which we will also denote by
-$S^*$ when there is no ambiguity. Let $L$ be the problem size, which is often
-(but not always) equal to $|\Omega|$.
-
-In general, we say we can efficiently optimize a function $f$ under constraint
-$K$ when we have a polynomial-time algorithm making adaptive value queries to
-$f$,which returns a set $S$ such that $S \in K$ and $f(S) \geq \alpha f(S^*)$
-with high probability and $\alpha$ an absolute constant.
-
-Here, we consider the scenario where we cannot make adaptive value queries, and
-in fact, where we cannot make queries at all! Instead, we suppose that we
-observe a polynomial number of set-value pairs $(S, f(S))$ where $S$ is taken
-from a known distribution $D$. We say we can efficiently \emph{passively
-optimize} $f$ under distribution $D$ or $D-$optimize $f$ under constraints $K$
-when, after observing ${\cal O}(L^c)$ set-value pairs from $D$ where $c > 0$ is
-an absolute constant, we can return a set $S$ such that $S \in K$ and $f(S)
-\geq \alpha f(S^*)$ with high probability and $\alpha$ an absolute constant.
-
-In the case of \emph{passive} observations of set-value pairs under a
-distribution $D$ for a function $f$, recent research has focused on whether we
-can efficiently and approximately \emph{learn} $f$. This was formalized in the
-PMAC model from \cite{balcan2011learning}. When thinking about passive
-optimization, it is necessary to understand the link between being able to
- $D-PMAC$ learn $f$ and being able to $D-$optimize $f$.
-
-\subsection{Additive function}
-
-We consider here the simple case of additive functions. A function $f$ is
-additive if there exists a weight vector $(w_s)_{s \in \Omega}$ such that
-$\forall S \subseteq \Omega, \ f(S) = \sum_{s \in S} w_s$. We will sometimes
-adopt the notation $w \equiv f(\Omega)$.
-
-\subsubsection{Inverting the system}\label{subsec:invert_the_system}
-
-Suppose we have observed $n^c$ set-value pairs ${(S_j, f(S_j))}_{j \in N}$ with
-$S_j \sim D$ where $n \equiv |\Omega|$. Consider the $n^c \times n$ matrix $A$
-where for all $i$, the row $A_i = \chi_{S_i}$, the indicator vector of set
-$S_i$. Let $B$ be the $n^c \times 1$ vector such that $\forall i, b_j \equiv
-f(S_j)$. It is easy to see that if $w$ is the $n \times 1$ corresponding weight
-vector for $f$ then:
-\begin{displaymath}
- A w = B
-\end{displaymath}
-
-Note that if $A$ has full column rank, then we can solve for $w$ exactly and
-also optimize $f$ under any cardinality constraint. We can therefore cast the
-question of $D-$learning and $D-$optimizing $f$ as a random matrix theory
-problem: what is the probability that after $n^c$ for $c > 0$ independent
-samples from $D$, the matrix $A$ will have full rank? See
-section~\ref{sec:matrix_theory}
-
-\paragraph{Extension}
-Note that the previous reasoning can easily be extended to any \emph{almost}
-additive function. Consider a function $g$ such that there exists $\alpha > 0$
-and $\beta > 0$ and an additive function $f$ such that $\forall S, \alpha f(S)
-\leq g(S) \leq \beta f(S)$, then by solving for $\max_{S\in K} f(S)$ we have a
-$\alpha/\beta$-approximation to the optimum of $g$ since:
-
-\begin{displaymath}
-g(S^*) \geq \alpha f(S^*) \geq \alpha f(OPT) \geq
-\frac{\alpha}{\beta} g(OPT)
-\end{displaymath}
-
-where $OPT \in \arg \max_{S \in K} g(S)$. This can be taken one step further by
-considering a function $g$ such that there exists $\alpha, \beta >0$, an
-additive function $f$ and a bijective univariate function $\phi$, such that
-$\forall S, \alpha \phi(f(S)) \leq g(S) \leq \beta \phi(f(S))$. In this case, we
-solve the system $A w = \phi^{-1}(B)$ and obtain once again an
-$\alpha/\beta$-approximation to the optimum of $g$.
-
-\begin{remark}
-Note that here $D-$optimizing $f$ is easy because $D-$learning $f$ is easy. We
-would like to understand whether being able to $D-$learn $f$ is really
-necessary to $D-$optimizing it. In fact, many results for PMAC-learning more
-complex functions, such as general submodular functions, are negative. Can we
-hope to find positive results in cases where PMAC-learning is impossible?
-\end{remark}
-
-\subsubsection{Average weight method}
-
-We consider here another method to $D-$optimizing $f$, which only requires
-$D-$learning $f$ approximately. Note that for every element $i \in \Omega$, and
-for a \emph{product} distribution $D$:
-\begin{displaymath}
- \mathbb{E}_{S \sim D}(f(S)|i \in S) - \mathbb{E}_{S \sim D}(f(S) | i \notin
- S) = \sum_{j \neq i \in \Omega} w_s \left(\mathbb{P}(j\in S|i \in S) -
- \mathbb{P}(j \in S | i \notin S)\right) + w_i(1 - 0) = w_i
-\end{displaymath}
-
-Let $O$ be the collection of all sets $S$ for which we have observed $f(S)$ and
-let $O_i \equiv \{S \in O : i \in S\}$ and $O^c_i \equiv \{ S\in O: i \notin S
-\}$. If $O_i$ and $O^c_i$ are non-empty, define the following weight estimator:
-\begin{displaymath}
- \hat W_i \equiv \frac{1}{|O_i|} \sum_{S \in O_i} f(S) - \frac{1}{|O_i^c|}
- \sum_{S \in O_i^c} f(S)
-\end{displaymath}
-
-If $D$ is a product distribution such that $ \exists c > 0, \forall i,
-\mathbb{P}(i) \geq c$, it is
-easy to show that $\forall i \in
-\Omega,\ \hat W_i \rightarrow_{|O| \rightarrow +\infty} w_i$
-By using standard concentration bounds, we can hope to obtain within $poly(n,
-\frac{1}{\epsilon})$ observations:
-
-
-%For every node $i$, we compute the \emph{average weight of every set containing
-%element $i$}. Let $w_i$ be
-%the weight of element $i$, $w \equiv f(\Omega) = \sum_{i \in \Omega} w_i$ and
-%$p \equiv \frac{k}{n}$, then $$\forall i \in \Omega, \mathbb{E}_{S \sim
-%D_p}\left[f(S)| i \in S\right] = pw + (1 -p)w_i$$
-
-%Note that the average weight of every set containing element $i$ preserves the
-%ranking of the weights of the elements. For observations ${(S_j, f(S_j))}_{j \in
-%N}$ and for $N_i \equiv |\{S : i \in S\}|$, we define the following estimator:
-
-%\begin{equation} \forall i \in \Omega, w_i^{N_i} \equiv \frac{1}{N_i}\sum_{S |
-%i \in S} \frac{f(S) - pw}{1-p} \end{equation}
-
-%As shown above, $w_i^{N_i} \rightarrow w_i$ as $N_i \rightarrow +\infty$. We
-%can obtain a concentration bound of $w_i^{N_i}$ around $w_i$, using Hoeffding's
-%lemma:
-
-%\begin{equation} \mathbb{P}\left(\middle|w_i^{N_i} - w_i \middle| \geq
-%\epsilon w_i \right) \leq 2e^{-2(1-p)N_i\frac{\epsilon^2 w_i^2}{w^2}}
-%\end{equation}
-
-%\emph{TODO:multiplicative boudns are very bad for zero weights\dots Need to look
-%at additive bounds for these zeros.}
-
-%For $N_i$ sufficiently large for each element $i$, we have $\forall i \in
-%\Omega, (1-\epsilon) w_i \leq w_i^{N_i} \leq (1 + \epsilon) w_i$. Under this
-%assumption, if we choose the $k$ elements with largest estimated weight
-%$W_i^{N_i}$, we obtain a $\frac{1-\epsilon}{1+\epsilon}$-approximation to OPT,
-%where OPT is the value of the maximum weight set of $k$ elements for the
-%function $f$. To ensure that $N_i$ is sufficiently large for each element, we
-%note that $\mathbb{E}(N_i) = pN$ and use a Chernoff bound coupled with a
-%classic union bound:
-
-%\begin{equation} \mathbb{P}\left(\bigcup_{i \in \Omega} \left[N_i \leq
-%\frac{pN}{2}\right]\right) \leq \sum_{i\in \Omega} \mathbb{P}\left(N_i \leq
-%\frac{pN}{2}\right) \leq n e^{-\frac{pN}{8}} \end{equation}
-
-%As such, for $C > 0$ and $N \geq (C+1)\frac{8}{p}\log n$, we have $\forall i
-%\in \Omega, N_i \geq \frac{pN}{2}$ with probability at least $1-\frac{1}{n^C}$
-
-%\begin{proposition} Assume that $N$ pairs of set-value ${(S_j, f(S_j))}_{j \in
- %N}$ are observed, where $S_j \sim D_p$ and $p \equiv \frac{k}{n}$. If $N >
- %XXX$, then we can $\epsilon$-learn $f$ and optimize it to a
- %$(1+\epsilon)/(1-\epsilon)$ factor for any cardinality constraint with
- %probability $XXX$. \end{proposition}
-
-\subsection{General submodular functions}
-
-\subsection{Parametric submodular functions}
-
-\textbf{Note:} all known examples of submodular functions are parametric. The
-question is not parametric vs non-parametric but whether or not the number of
-parameters is polynomial or exponential in $n$ (the size of the ground set).
-For all examples I know except martroid rank functions, it seems to be
-polynomial.
-
-\subsubsection{Influence Functions}
-
-Let $G = (V, E)$ be a weighted directed graph. Without loss of generality, we
-can assign a weight $p_{u,v} \in [0,1]$ to every possible edge $(u,v) \in V^2$.
-Let $m$ be the number of non-zero edges of $G$. Let $\sigma_G(S, p)$ be the
-influence of the set $S \subseteq V$ in $G$ under the IC model with parameters
-$p$.
-
-Recall from \cite{Kempe:03} that:
-\begin{equation}
- \sigma_G(S, p) = \sum_{v\in V} \P_{G_p}\big[r_{G_p}(S\leadsto v)\big]
-\end{equation}
-where $G_p$ is a random graph where each edge $(u,v)\in E$ appears with
-probability $p_{u,v}$ and $r_{G_p}(S\leadsto v)$ is the indicator variable of
-\emph{there exists a path from $S$ to $v$ in $G_p$}.
-
-\begin{claim}
-\label{cla:oracle}
-If for all $(u,v) \in V^2$, $p_{u,v} \geq p'_{u,v} \geq p_{u,v}
-- \frac{1}{\alpha m}$, then:
-\begin{displaymath}
- \forall S \subseteq V,\, \sigma_{G}(S, p) \geq \sigma_{G}(S,p') \geq (1
- - 1/\alpha) \sigma_{G}(S,p)
-\end{displaymath}
-\end{claim}
-
-\begin{proof}
- We define two coupled random graphs $G_p$ and $G_p'$ as follows: for each
- edge $(u,v)\in E$, draw a uniform random variable $\mathcal{U}_{u,v}\in
- [0,1]$. Include $(u,v)$ in $G_p$ (resp. $G_{p'}$) iff
- $\mathcal{U}_{u,v}\leq p_{u,v}$ (resp. $\mathcal{U}_{u,v}\leq p'_{u,v}$).
- It is clear from the construction that each edge $(u,v)$ will be present in
- $G_p$ (resp. $G_p'$) with probability $p_{u,v}$ (resp. $p'_{u,v}$). Hence:
- \begin{displaymath}
- \sigma_G(S, p) = \sum_{v\in V} \P_{G_p}\big[r_{G_p}(S\leadsto v)\big]
- \text{ and }
- \sigma_G(S, p') = \sum_{v\in V} \P_{G_p'}\big[r_{G_p'}(S\leadsto v)\big]
- \end{displaymath}
-
- By construction $G_{p'}$ is always a subgraph of $G_p$, i.e
- $r_{G_p'}(S\leadsto v)\leq r_{G_p}(S\leadsto v)$. This proves the left-hand
- side of the Claim's inequality.
-
- The probability that an edge is present in $G_p$ but not in $G_p'$ is at
- most $\frac{1}{\alpha m}$, so with probability $\left(1-\frac{1}{\alpha
- m}\right)^m$, $G_p$ and $G_p'$ have the same set of edges. This implies that:
- \begin{displaymath} \P_{G_{p'}}\big[r_{G_p'}(S\leadsto v)\big]\geq
- \left(1-\frac{1}{\alpha m}\right)^m\P_{G_{p}}\big[r_{G_p}(S\leadsto v)\big]
- \end{displaymath}
- which proves the right-hand side of the claim after observing that
- $\left(1-\frac{1}{\alpha m}\right)^m\geq 1-\frac{1}{\alpha}$ with equality
- iff $m=1$.
-\end{proof}
-
- We can use Claim~\ref{cla:oracle} to find a constant factor approximation
- algorithm to maximising influence on $G$ by maximising influence on $G'$. For
- $k \in \mathbb{N}^*$, let $O_k \in \arg\max_{|S| \leq k} \sigma_G(S)$ and
- $\sigma_{G}^* = \sigma_G(O_k)$ where we omit the $k$ when it is unambiguous.
-
-
-\begin{proposition}
-\label{prop:approx_optim}
-Suppose we have an unknown graph $G$ and a known graph $G'$ such that $V = V'$
-and for all $(u,v) \in V^2, |p_{u,v} - p_{u,v}'| \leq \frac{1}{\alpha m}$.
-Then for all $k \in \mathbb{N}^*$, we can find a set $\hat O_k$ such that
-$\sigma_{G}(\hat O_k) \geq (1 - e^{\frac{2}{\alpha} - 1}) \sigma^*_{G}$
-\end{proposition}
-
-\begin{proof} For every edge $(u,v) \in V^2$, let $\hat p = p'_{u,v} -
- \frac{1}{\alpha m}$. We are now in the conditions of Claim~\ref{cla:oracle}
- with $\alpha \leftarrow \alpha/2$. We return the set $\hat O_k$ obtained by
- greedy maximisation on $\hat G$. It is a classic exercise to show then that
- $\sigma_G(\hat O_k) \geq 1 - e^{\frac{2}{\alpha} - 1}$ (see Pset 1, CS284r).
-\end{proof}
-
-A small note on the approximation factor: it is only $>0$ for $\alpha > 2$.
-Note that $\alpha \geq 7 \implies 1 - e^{\frac{2}{\alpha} - 1} \geq
-\frac{1}{2}$ and that it converges to $(1 - 1/e)$ which is the best possible
-polynomial-time approximation ratio to influence maximisation unless $P = NP$.
-Also note that in the limit of large $m$, $(1 -\frac{1}{\alpha m})^m
-\rightarrow \exp(-1/\alpha)$ and the approximation ratio goes to $1 -
-\exp(-\exp(-2/\alpha))$.
-
-\subsubsection{Active set selection of stationary Gaussian Processes}
-
-\section{Passive Optimization vs. Passive Learning}
-
-\subsection{Failed Attempt: returning max of observations}
-
-This doesn't work. Give examples as to why! Remember that there are strong
-concentration results for submodular functions -> look at expected value of
-observed sets
-
-\subsection{Example where optimization possible, learning impossible}
-
-Recall the matroid construction from~\cite{balcan2011learning}:
-\begin{theorem}
- For any $k$ with $k = 2^{o(n^{1/3})}$, there exists a family of sets ${\cal A}
- \subseteq2^{[n]}$ and a family of matroids $\cal{M} = \{M_{\cal{B}} :
- \cal{B} \subseteq\cal{A} \}$ such that:
- \begin{itemize}
- \item $|{\cal A}| = k$ and $|A| = n^{1/3}$ for every $A \in \cal{A}$
- \item For every $\cal{B} \subseteq\cal{A}$ and every $A \in \cal{A}$, we
- have:
- \begin{align*}
- \text{rank}_{M_{\cal{B}}}(A) & = 8 \log k \ if A\in{\cal B} \\
- & = |A| \ if A\in {\cal A}\backslash{\cal B}
- \end{align*}
- \end{itemize}
-\end{theorem}
-
-Consider the following subset of the above family of matroids: ${\cal
-M}^{\epsilon} = \{M_{\cal B} : {\cal B} \subseteq{\cal A} \wedge |{\cal
-A}\backslash{\cal B}| \geq \epsilon|{\cal A}|\}$ for $k = 2^{n^{1/6}}$.
-Consider an \emph{unknown} function $f$, corresponding to the rank function of
-one of the matroids $M_{\cal B}$ from ${\cal M}^{\epsilon}$. Note that as long
-as we observe \emph{one} set from ${\cal A} \backslash {\cal B}$, we can
-optimize $f$ exactly! Indeed, the largest possible value for $f$ under
-cardinality constraint $n^{1/3}$ is $\max_{A\in 2^{[n]}} |A| = n^{1/3}$.
-
-One example of a distribution under which this occurs with probability at least
-a constant is $D_u$, the uniform distribution over all sets of ${\cal A}$. For
-$c>0$, after $n^c$ observations $O \equiv (S_i, f(S_i))_i$ for $S_i \sim D_u$,
-we will observe at least one element from $\cal{A}\backslash\cal{B}$ with
-constant probability:
-
-\begin{equation} \nonumber \mathbb{P}(\bigcup_{S_i} S_i \in {\cal
-A}\backslash{\cal B}) \geq 1 - (1 - \epsilon)^{n^c} \approx \epsilon n^c
-\end{equation}
-
-However, it follows from the analysis of~\cite{balcan2011learning} that we
-cannot learn $f$ under any distribution, even with active value queries!
-Indeed, for any polynomially-sized set of observations, there exists a
-super-polynomially number of functions in ${\cal M^1}$ which coincide on this
-set of observations, but which take very different values outside of this set
-of observations: $8n^{1/6}$ for $A \in {\cal B}$ and $n^{1/3}$ for $A \in {\cal
-A}\backslash {\cal B}$.
-
-{\bf TODO:} A cleaner simpler example would be nice.
-
-\section{Meeting notes: 04.03.2015}
-
-Consider the following function:
-\begin{displaymath}
- g(S) = \max\left\{\sqrt{n}|X\cap S|, |S|\right\}
-\end{displaymath}
-where $|X|=\sqrt{n}$. Assume that you are given polynomially many samples where
-each element is included with probability $1/2$. Then with high probability all
-the samples will have size roughly $n/2$, so you will observe $g(S)=|S|$ with
-high probability.
-
-\paragraph{Claim 1:} $g$ is PAC-learnable because if you output $|S|$ then you
-will be correct with high probability is $S$ is drawn from the same
-distribution as above.
-
-\paragraph{Claim 2:} $g$ is not optimizable under budget $\sqrt{n}$ because you
-never learn anything about $X$.
-
-\paragraph{Open Question:} Cook a similar example where $g$ is submodular and
-where you are observing sets of the same size as your budget.
-
-\paragraph{Positive results:} Try to obtain guarantees about learning
-parameters of parametric submodular functions and show whether or not these
-guarantees are sufficient for optimization. First look at learning weights in
-a cover function. Maybe facility location? Sums of concave over modular are
-probably too hard because of the connection to neural networks.
-
-\section{Which learning guarantees imply optimization?}
-
-Here, we consider the following question: which learning guarantees imply
-optimization? For example, \cite{TODO} provides the following guarantee for
-cover functions:
-
-\begin{theorem}
-There exists an algorithm such that for any $\epsilon>0$ given random and
-uniform examples of a coverage function $c$ outputs a hypothesis, which is also
-a coverage function $h$, such that with probability $2/3$: $\mathbb{E}_{\cal
-U}[|h(x) - c(x)|] \leq \epsilon$. The algorithm runs in time $\tilde {\cal O}(n)
-\cdot \text{poly}(s/\epsilon)$ and uses $\log(n)\cdot \text{poly}(s/epsilon)$
-and examples, where $s = \min\{size(c), (1/\epsilon)^{\log(1/\epsilon)}\}$.
-\end{theorem}
-
-We would like to understand to what extent this $\ell1$-bound allows us to
-optimize the coverage function $c$ under cardinality constraints using the
-hypothesis $h$. Let us consider the simpler case of an additive function, and
-suppose we have a similar guarantee: $\mathbb{E}_{x \sim {\cal U}}[|h(x) -
-c(x)|]$ where $\forall x, c(x) \equiv \sum_i w_i x_i$ and $h(x) \equiv \sum_i
-\hat w_i x_i$. Can we find a bound on $\|w - \hat w\|_{\infty}$?
-
-As it turns out, yes. Let $\forall i, w_i - \hat w_i \equiv \alpha_i$ and let
-$V(x) \equiv |h(x) - c(x)| = |\sum_{i} \alpha_i x_i |$. Consider the collection
-of good sets $\cal G \equiv \{S : v(S) < 4\epsilon\}$. We claim that $|{\cal G}|
-\geq \frac{3}{4}c\dot2^n$. Suppose the contrary, there is at least a quarter of
-the sets which have value $v(S) > 4\epsilon$ such that $\mathbb{E}_{x \sim {\cal
-U}}[|v(x)|] \geq \frac{1}{2^n}\sum_{S \in {\cal G}^c} |v(S)| >
-\frac{1}{4}\cdot4\epsilon = \epsilon$ which is a contradiction. Consider element
-$i$ such that $|\alpha_i| \equiv \|\alpha\|_{\infty}$. Consider the collection
-of sets which contain $i$: ${\cal S}_i \equiv \{S : i \in S\}$. Notice that
-$|{\cal S}_i| = |{\cal S}_i^c| = 2^{n-1}$. Therefore, $|{\cal G} \cap {\cal
-S}_i^c| \geq \frac{1}{4}\cdot 2^n$. For all sets $S$ in ${\cal G} \cap {\cal
-S}_i^c$, $v(S\cup\{j\}) \geq \alpha_i - 4\epsilon$. It follows that
-$\mathbb{E}_{x \sim {\cal U}}[|v(x)|] \geq \frac{1}{4}(\alpha_j - 4\epsilon)$
-and therefore we have $\|w - \hat w\|_{\infty} \leq 8 \epsilon$.
-
-\bibliography{optimize} \bibliographystyle{apalike}
-
-
-\end{document}